octavio_dingus@lemmy.world to Technology@lemmy.worldEnglish · 1 day agoReddit temporarily bans r/WhitePeopleTwitter after Elon Musk claimed it had ‘broken the law’www.engadget.comexternal-linkmessage-square49fedilinkarrow-up1426arrow-down19cross-posted to: enoughmuskspam@lemmy.world
arrow-up1417arrow-down1external-linkReddit temporarily bans r/WhitePeopleTwitter after Elon Musk claimed it had ‘broken the law’www.engadget.comoctavio_dingus@lemmy.world to Technology@lemmy.worldEnglish · 1 day agomessage-square49fedilinkcross-posted to: enoughmuskspam@lemmy.world
minus-squareqantravon@lemmy.worldlinkfedilinkEnglisharrow-up10·23 hours agoFor the phrase, “broken” specifically means “stopped”, and the clock is analog. If the hands don’t turn, then they will be correct twice per day.
minus-squareVintageGenious@sh.itjust.workslinkfedilinkEnglisharrow-up1·edit-29 hours agoThanks makes more sense! Idk why the downvotes… Because in the case of an offset it would always be wrong and in the case of a speed change. In the general case, with clock speed a and offset b: a x + b ≡ x (mod 12) a x + b = x + 12k If a=1, normal speed with offset, b = 12k ≡ 0 (mod 12) So it works for any multiple of 12h offset (ie no offset) If a≠1, x = (12k - b)/(a-1) It isn’t always in a day, so you can end up having to wait multiple days for it to be right
For the phrase, “broken” specifically means “stopped”, and the clock is analog. If the hands don’t turn, then they will be correct twice per day.
Thanks makes more sense! Idk why the downvotes… Because in the case of an offset it would always be wrong and in the case of a speed change.
In the general case, with clock speed a and offset b:
If a=1, normal speed with offset,
So it works for any multiple of 12h offset (ie no offset)
If a≠1,
It isn’t always in a day, so you can end up having to wait multiple days for it to be right