Hi all! I have always only used sed with s///, becouse I’ve never been able to figure out how to properly make use of its full capabilities. Right now, I’m trying to filter the output of df -h --output=avail,source to only get the available space from /dev/dm-2 (let’s ignore that I just realized df accepts a device as parameter, which clearly solves my problem).

This is the command I’m using, which works:

df -h --output=avail,source \
    | grep /dev/dm-2 \
    | sed -E 's/^[[:blank:]]*([0-9]+(G|M|K)).*$/\1/

However, it makes use of grep, and I’d like to get rid of it. So I’ve tried with a combiantion of t, T, //d and some other stuff, but onestly the output I get makes no sense to me, and I can’t figure out what I should do instead.

In short, my question is: given the following output

$ df -h --output=avail,source 
Avail Filesystem
  87G /dev/dm-2
 1.6G tmpfs
  61K efivarfs
  10M dev
...

How do I only get 87G using only sed as a filter?

EDIT:

Nevermind, I’ve figured it out…

$ df -h --output=avail,source \
    | sed -E 's/^[[:blank:]]*([0-9]+(G|M|K))[[:blank:]]+(\/dev\/dm-2).*$/\1/; t; /.*/d'
85G
  • bizdelnick@lemmy.ml
    2·
    9 days ago

    You can then combine this with s (substitute):

    sed '/myregex/ s/from/to/ p'

    This is not combining commands. In your example p is a modifier to the s/// command.

    • gnuhaut@lemmy.ml
      2·
      8 days ago

      Yeah you’re right, thanks. I did figure this out on my own already, see my other comment:

      Oh yeah that, so technically (and I was confused about this), the p in s/from/to/p is not the same as the p command, it’s a flag for the s command that tells it to print the output.